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9x^2+5x-8=3x^2+2x+10
We move all terms to the left:
9x^2+5x-8-(3x^2+2x+10)=0
We get rid of parentheses
9x^2-3x^2+5x-2x-10-8=0
We add all the numbers together, and all the variables
6x^2+3x-18=0
a = 6; b = 3; c = -18;
Δ = b2-4ac
Δ = 32-4·6·(-18)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-21}{2*6}=\frac{-24}{12} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+21}{2*6}=\frac{18}{12} =1+1/2 $
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